Question

Justin is marking a border for a garden. He walks 200 feet to the east, then turns and

walks 120 feet due south, before finally walking in a straight line back to his original

starting point. To the nearest foot, how far does Justin walk in all?

Answer

feet

Answer 1

d = 233.23 feet

Explanation:

Given that,

Justin walks 200 feet to the east, then turns and walks 120 feet due south.

We need to find the total distance walked by Justin. Let the distance be d.

We can use the Pythagoras theorem to find it such that,

`d=√(d_1^2+d_2^2) \\\\d=√(200^2+120^2) \\\\d=233.24\ feet`

So, he walk 233.23 feet in all.