Question

A photographer shines a camera light at a particular painting forming an angle of 40° with the camera platform. If the light is 58 feet from the wall where the painting hangs, how high above the platform is the painting?

Answer 1

Let y be the height above the camera platform of the painting.

tan (40degrees) = y/58

y = 58[tan(40)] = 58(0.8391) = 48.67 feet.

y = 48.67 feet

Explanation: