Question

Find the equation of the line that passes through the point (6,14) and is parallel to the equation below.

y =
1 - 4
OA.
y = r - 18
OB.
y = - + 20
y = ģx + 10
OC.
OD
y =
- 52 + 8
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Answer 1

y = 2x/3 + 10 ; C

Explanation:

To write the equation of a straight line, we have the general form as;

y = mx + b

where m is the slope and b is the y intercept

Mathematically from the equation given, the slope value is 2/3

When two lines are parallel to each other , the value of their slopes are the same

What this mean is that the value of the slope of the second line is 2/3

So we have the second line as;

y = 2x/3 + b

To get the value of b, we use the given point where the line passes through

The given point according to the question is the point (6,14)

so using this coordinates, we have

14 = 2/3(6) + b

14 = 4 + b

b = 14-4

b = 10

So the equation of the new line is;

y= 2/3x + 10