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What is the solution to the equation startroot 2n+28 endroot -4 startroot n endroot =0 n=2 n=4 n=7 n=14

What is the solution to the equation startroot 2n+28 endroot -4 startroot n endroot =0 n=2 n=4 n=7 n=14
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5 votes
What is the solution to the equation startroot 2n+28 endroot -4 startroot n endroot =0 n=2 n=4 n=7 n=14

asked
User Aaberg
by
8.9k points

2 Answers

4 votes

Answer:

C

Explanation:

EDGE

answered
User Prathamesh Doke
by
8.1k points
5 votes
the answer is 7 because yeah
answered
User Ismael Miguel
by
7.5k points
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