Question

What is the perimeter, in feet, of a rectangle whose length is twice its width and whose width is 5 feet

Answer 1

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Answer:

30 ft

Explanation:

The width is 5 ft. The length is twice that, so is 10 ft. The perimeter is given by the formula ...

P = 2(L +W)

P = 2(10 ft + 5 ft) = 2(15 ft)

P = 30 ft

The perimeter of the rectangle is 30 feet.