Find a value of k such that kx2 + 12x − 4 = 0 has one real-number solution. Explain.

Question

asked Jul 16, 2022 71.9k views

2 Answers

Bert H · Answer 1 · 2022-07-22T03:50:40+0000

Answer: if x is to the 2 power then

kx^2+12x-4=0 Add 4 to the both sides

kx^2+12x=4 Divide both sides by 12

kx^2=1/3x square root the both sides

k=0.6x

Explanation: