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12. Find the differential coefficient of (x2+7) (x2+10)​

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User Adrian W
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1 Answer

8 votes

Answer:


We \: need \: to \: find \\ the \: differential \\ coefficient \: of \: the \\ function  \: x2logxsinx  \\ with \: respect \: to \:  x. \\Let  \: y=x \: 2logxsinx \\ We \: need \\ to \: find \:  dxdy. \\Consider  \\ y=x \: 2logxsinx \\ dxdy=dxd(x2)logxsinx+x2dxd(logxsinx) \\  =2x(logxsinx)+x2[sinxdxd(logx)+logxdxd(sinx)] \\ =2x(logxsinx)+x2[xsinx+logxcosx] \\ dxdy=2x(logxsinx)+xsinx+x2logxcosx

answered
User David Dostal
by
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