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How many solutions would there be for the following system of equations? y = 3x - 5 67 – 2g = 10 A 1 Solution B 2 Solutions c) No solution D Infinitely Many solutions​

How many solutions would there be for the following system of equations? y = 3x - 5 67 – 2g-example-1
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User Rolgalan
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7.4k points

1 Answer

4 votes

Answer:

D

Explanation:

Given the 2 equations

y = 3x - 5 → (1)

6x - 2y = 10 → (2)

Substitute y = 3x - 5 into (2)

6x - 2(3x - 5) = 10

6x - 6x + 10 = 10 ( subtract 10 from both sides )

6x - 6x = 0 , that is

0 = 0 ← True

This indicates the system has infinitely many solutions → D

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