Question

Give the equation of the line which is perpendicular to y = 5x + 6 and goes through the point (- 15, 2)​

Answer 1

x+5y+5=0

Explanation:

y=5x+6

Therefore the gradient of the line = 5

Now reciprocate the gradient and negate it

i.e -1/5

let (x,y) and (-15,2) be points on the line

y-2/x-(-15)=-⅕

5y-10=-x-15

5y-10+15+x=0

x+5y+5=0

Therefore the equation of the line =

x+5y+5=0