Question

The table shows the number of hours Mr. Farley and Mr. Samuels spent advising clients each week for a 6 week period. Determine the difference between the mean of the data for Mr. Farley and the mean of the data for Mr. Samuels. Round to the nearest tenth.

PLEASE HELP ASAP NO LINKS AND SILLY ANSWERS PLEASE

Answer 1

1.2

Explanation:

Mr. Farley's Mean:

(54 + 47 + 65 + 78 + 81 + 75)/6

66.67

Mr. Samuel's Mean:

(68 + 49 + 70 + 57 + 86 + 63)/6

65.5

Difference:

66.67 - 65.5

1.17

1.2

Answer 2

Answer: 1

Explanation:

To get the average for Mr. Farley's hours, you add up all his hours to get 400. If you divide that by 6, you get 66.666, which can be rounded to 67. To get Mr. Samuel's hours, you do the same and add up to 393 then divide to get 65.6, which can be rounded to 66. Subtract 66 from 67 to get 1. Hope this helps!!