2 {x }^(2) - 10x - 4 = 0 ​

Question

`2 {x }^(2) - 10x - 4 = 0`
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Answer 1

`x_1 = (5 - √(33))/(2)\\x_2 = (5 + √(33))/(2)`

That's assuming we were supposed to solve for x.

Explanation:

`ax^2 + bx + c = 0\vspace{3pt}\\\Delta = b^2 - 4ac\vspace{4pt}\\x = (-b \pm √(\Delta))/(2a)\\\\2x^2 - 10x - 4 = 0\\x^2 - 5x - 2 = 0\\\Delta = (-5)^2 - 4\cdot 1\cdot (-2) = 25 + 8 = 33\\x_1 = (5 - √(33))/(2)\\x_2 = (5 + √(33))/(2)`

Answer 2

see below

Explanation:

I'm assuming you want to find the roots for this equation?

using the quadratic formula:
`x_(1,\:2)=(-\left(-10\right)\pm √(\left(-10\right)^2-4\cdot \:2\left(-4\right)))/(2\cdot \:2)`

`x=(5+√(33))/(2)` &
`\:x=(5-√(33))/(2)`