asked 74.9k views
0 votes
A gas has an initial pressure of 2065 mmHg and temperature of 416 K. What is

the new pressure in atm if the temperature is cooled to 382 K?

asked
User Tpow
by
8.5k points

1 Answer

4 votes

Answer:

1896 mmHg

Step-by-step explanation:

P1/T1 = P2/T2

P1 = 2065 mmHg

T1 = 416 K

P2 = ?

T2 = 382 K

Solve for P2 --> P2 = P1T2/T1

P2 = (2065 mmHg)(382 K) / (416 K) = 1896 mmHg

answered
User Earthmover
by
8.0k points
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