Answer:
This quadratic has two unequal, imaginary roots.
Explanation:
y = 3x^2 + 8 is a quadratic function, and (like all quadratics) it has two roots. In this case they happen to be different (unequal), as well as imaginary.
Setting y = 3x^2 + 8 = 0, we get:
3x^2 = -8, or
x^2 = -8/3
Taking the square root of both sides, we get
x = ±i√(8/3) (2 imaginary roots)