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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=22°, and DB = 44 feet. Find the length of BC to the nearest tenth of a foot.

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=22°, and DB = 44 feet. Find the length of BC to the nearest tenth of a foot.
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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=22°, and DB = 44 feet. Find the length of BC to the nearest tenth of a foot.

asked
User Udi Meiri
by
8.5k points

1 Answer

4 votes

Answer:47.5

Explanation:

answered
User Bibhu
by
8.2k points
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