asked 81.6k views
20 votes
Janine inflated a ball to a radius of 18 cm and another ball to a radius of 12 cm. How much greater was the volume of air in the larger ball than the smaller ball? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box. Cm³.

asked
User Cryss
by
7.7k points

1 Answer

1 vote

Answer:

Difference of volume of air =
17182.08cm^(3)

Explanation:

Radius of ball = 18 cm

Volume of big ball =
(3)/(4) \pi o^(3)

= 4/3 x * 14 X 18
^(3)

= 7324g * g2/ 3

= 24416.64cm^3

Radious of another (small ball) = 12 cm

Volume of small ball =
(3)/(4) \pi R^(3)

= 4/3 x 3 * 14 X 12^3

= 21703.68/ 3

= 7234 * 56cm^3

Difference of volume =
v_(b) -v _(s)

= 24416 * 64 - 7234 * 56cm^3

= 17182 * 08 cm^3

answered
User Scomes
by
8.2k points
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