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Factor completely 21x^3+35x^2+9x+15

Factor completely 21x^3+35x^2+9x+15
asked 39.3k views
2 votes
Factor completely 21x^3+35x^2+9x+15

asked
User Dude Dawg
by
8.3k points

1 Answer

4 votes

Answer:

(3x+5)(7x^2+3)

Explanation:

Factor : 21x^3+35x^2+9x+15

21x^3+35x^2+9x+15

=(3x+5)(7x^2+3)

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Hope this helps!

answered
User Jim Heising
by
8.0k points
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