Question

Find the 64th term of the following arithmetic sequence .

12,19,26,33 ...

Answer 1

sequence 12,19,26,33

1st term = 12

comman difference = 19 - (12) = 7

comman term = a + (n-1)d

a= first term

d= difference

comman term = a + (n-1)d

= 12 + (n-1)(7)

= 12 +7n-7

= 7n +5

1st term --> n =1 = 7.1 + 5 = 12

2nd term --> n =2 = 7.2 + 5 = 14 + 5 = 19

64st term --> n =64 = 7.64+ 5 = 448+5 = 453

Explanation: