Question

Which is the correct number of moles of nitrogen monoxide that is produced from 13.2 moles of oxygen gas in the presence of excess ammonia (NH3)?

Answer 1

10.56 moles of NO will be produced

Step-by-step explanation:

The balanced reaction of ammonia, NH₃ with oxygen, O₂ is:

4NH₃ + 5O₂ → 4NO + 6H₂O

Where 5 moles of oxygen react with an excess of ammonia to produce 4 moles of nitrogen monoxude.

If 13.2 moles of O₂ react:

13.2 mol O₂ * (4 mol NO / 5 mol O₂) =

10.56 moles of NO will be produced