Question

The length of a rectangle is 3 times its width. If the length were increased by 2 inches and the width by 1 inch, the new perimeter would be 62 inches. What is the width and length of the rectangle? If w represents the width of the rectangle, then which equation could be used to solve for w?

2(4 w + 3) = 62
( w + 1)(3w + 2)=62
2(3 w + 3) = 62

Answer 1

2(4 w + 3) = 62

width =7 length = 21

Explanation:

For the perimeter you need :

2 times the width and 2 times the length (length =3w)

so

2(w+1) + 2 (3w+2) =

2w+2 + 6w+4 =

8w +6

you can factor this by:

2(4w+3)

8w +6= 62

8W = 56

w= 7 l= 21

2(7+1) + 2 (21+2)

16 + 46 = 62

Answer 2

pretty sure it’s the second option because length would be 3w+2
and width would be w+1 and with area you have to multiply so it would just be the (w+1)(3w+2)