asked 48.1k views
5 votes
Which of the following is a difference of cubes? x^6 + 27y^9 3x^9 - 64y^3 27x^{15} - 9y^3 125x^{21} - 64y^3

asked
User Yuval
by
7.9k points

2 Answers

3 votes

Answer:

D) 125x²¹- 64y³

Explanation:

A) x⁶ + 27y⁹ = (x²)³ + (3y³)³ - sum of cubes

B) 3x⁹ - 64y³ - the first term is not a cube

C) 27x¹⁵ - 9y³ - the second term is not a cube

D) 125x²¹- 64y³ = (5x⁷)³ - (4y)³ - difference of cubes

Correct option is the last one

answered
User M Faheem Rajput
by
8.1k points
2 votes

Answer:

  • D) 125x²¹- 64y³

Explanation:

  • A) x⁶ + 27y⁹ = (x²)³ + (3y³)³ - sum of cubes
  • B) 3x⁹ - 64y³ - the first term is not a cube
  • C) 27x¹⁵ - 9y³ - the second term is not a cube
  • D) 125x²¹- 64y³ = (5x⁷)³ - (4y)³ - difference of cubes

Correct option is the last one

answered
User Piyush Bansal
by
8.1k points

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