Answer:
Explanation:
If the derivative of g(x) with respect to x (denoted d/dx g(x)) is equal to 0, then the derivative of the product g(x)sin(x) with respect to x can be found using the product rule for derivatives.
The product rule states that if f(x) and g(x) are two functions, then the derivative of the product f(x)g(x) with respect to x is given by:
d/dx (f(x)g(x)) = f(x) * d/dx g(x) + g(x) * d/dx f(x)
In our case, f(x) is g(x) and g(x) is sin(x). Substituting these values into the equation above, we get:
d/dx (g(x)sin(x)) = g(x) * d/dx sin(x) + sin(x) * d/dx g(x)
Since the derivative of sin(x) with respect to x is cos(x) and the derivative of g(x) with respect to x is 0, we can simplify this expression to:
d/dx (g(x)sin(x)) = 0 * cos(x) + sin(x) * 0
Which simplifies to:
d/dx (g(x)sin(x)) = 0
Therefore, if the derivative of g(x) with respect to x is equal to 0, then the derivative of the product g(x)sin(x) with respect to x is also equal to 0.