Question

Solve the triangle PLEASEEEEEE

Answer 1

Part 1

`a=\sqrt{12^2 + 21^2 -2(12)(21) \cos 35^(\circ)} \approx \boxed{13}`

Part 2

`(\sin B)/(b)=(\sin A)/(a)\\\\\sin B=(b\sin A)/(a)\\\\\sin B=\frac{12 \sin 35^(\circ)}{\sqrt{12^2 +21^2 -2(12)(21) \cos 35^(\circ)}}\\\\B=\sin^(-1) \left(\frac{12\sin 35^(\circ)}{\sqrt{12^2 +21^2 -2(12)(21) \cos 35^(\circ)}} \right)\\\\B \approx \boxed{32^(\circ)}`

Part 3

`\angle C=180^(\circ)-\angle A -\angle B=\boxed{113^(\circ)}`