Question

in triangle ABC, AB = 6 cm, BC = 13cm and angle ACB = 23 degrees. Calculate angle BÁC, which is obtuse.

Answer 1

`\angle BAC=180^(\circ)-(13\sin 23^(\circ))/(6)`

Explanation:

`(\sin(\angle BAC))/(13)=(\sin 23^(\circ))/(6) \\ \\ \sin \angle BAC=(13\sin 23^(\circ))/(6) \\ \\ \angle BAC=180^(\circ)-(13\sin 23^(\circ))/(6)`