Question

Write an equation of a circle with a radius of 8 and a center of (3,-4)

Answer 1

Answer:
`(x-3)^2+(y+4)^2=64`

Explanation:

The equation of a circle is
`(x-h)^2+(y-k)^2=r^2`. h and k are the points of the center corresponding with x and y respectively. r is radius. All we have to do is plug the values in.

`(x-3)^2+(y-(-4))^2=8^2`

With our values plugged in, we can now simplify.

`(x-3)^2+(y+4)^2=64`

Therefore, our final equation is
`(x-3)^2+(y+4)^2=64`.