Question

What is the volume of 1.6 moles of a gas at 1.2 atm and 290K?

Answer 1

`V=31.745L.`

Step-by-step explanation:

1. Solve the equation of ideal gases for volume (the value with unit "L").

`R=(V(L)*atm)/(mol*k)\\ \\mol*k*R=V(L)*atm\\ \\V(L)=(mol*k*R)/(atm)`

2. Substitute the variables in formula with the given values.

`V(L)=((1.6 mol)(290K)(0.0821))/(1.2atm)`

3. Calculate.

`V=((1.6 mol)(290K)(0.0821))/(1.2atm)\\\\ V=31.745L`