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What is the volume of 1.78 moles of nitrogen gas (N2) at STP

asked
User Nhat
by
7.9k points

1 Answer

3 votes

Answer:


\huge\boxed{\sf v = 39.872\ dm\³}

Step-by-step explanation:

Given data:

Moles = n = 1.78 moles

Molar volume = V = 22.4 dm³

Required:

Volume = v = ?

Formula:

v = n × V

Solution:

v = 1.78 × 22.4

v = 39.872 dm³


\rule[225]{225}{2}

answered
User Jon Edmiston
by
8.1k points

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