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Show that (3x + 5)(x - 1)-3 = 3x² + 2x - 8​

Show that (3x + 5)(x - 1)-3 = 3x² + 2x - 8​
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Show that (3x + 5)(x - 1)-3 = 3x² + 2x - 8​

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User Cmhobbs
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2 Answers

3 votes
The answer is 0 because your subtracting all of the number added
answered
User Nate Hitze
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8.8k points
3 votes

Answer:


\tt \left(3x+5\right)\left(x-1\right)-3

Distribute:-


\tt 3x^2+2x-5-3


\tt -5-3=-8


\tt 3x^2+2x-8

Hope this help you!

answered
User Foslock
by
7.5k points
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