Question

Solve for w.
2w²-2w+32 = (w-5)²

Answer 1

`2w^2-2w+32=(w-5)(w-5)`

`2w^2-2w+32=w^2-10w+25`

Subtract
`w^2` from each side:

`w^2-2w+32=-10w+25`

Add
`10w` to each side:

`w^2+8w+32=25`

Subtract 25 from each side:

`w^2+8w+7=0`

Factor:

`(w+1)(w+7)` =0

Both solutions work, so w=-1 and w=-7