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Solve for y.
y² +4y+4=0

1 Answer

2 votes

Answer:

y=-2

Explanation:


y^2+4y+4=0\\y^2+2y+2y+4=0\\(y^2+2y)+(2y+4)=0\\y(y+2)+2(y+2)=0\\(y+2)=0\\and \\(y+2)=0\\y=-2


Proof:\\(-2)^2+4(-2)+4=0\\4+(-8)+4=0\\8-8=0\\0=0

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User Lomec
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