Question

Two asteroids are 75000 m apart one has a mass of 8 x 10^7 kg if the force of gravity between them is 1.14 what is the mass of the asteroid

3.4 x 10^11 kg
8.3 x 10 ^12 kg
1.2 x 10 ^12 kg
1.2 x 10^10 kg

Answer 1

1.2×10¹² kg

Step-by-step explanation:

from

`f = \frac{gm1m2 }{r {}^(2) }`

`m2 = \frac{fr {}^(2) }{gm1}`

`m2 = \frac{1.14 * (75000 { )}^(2) }{6.67 * {10}^( - 11) * 8 * {10}^(7) }`

HENCE M2= 1.2×10¹²kg