Question

What is the equation of a like that passes through (2,5) and (3,10) and has a y intercept of 7

Answer 1

y=5x+7

Explanation:

y=slope*x+y-intercept

slope=(10-5)/(3-2)=5/1=5

y-intercept is 7

y=5x+7

Answer 2

Answer: y = 5x + 7

Explanation:

To write an equation you can use the y intercept and the slope.

slope = 10 - 5 / 3 - 2 = 5/1 = 5

y = mx + b m = slope b = y int

y = 5x + 7