Question

If a 62 kg panther sits in a tree 1.3 meters above the ground, how much gravitational potential energy does it have?

If the air resistance cause the panther to lose 200 J of energy as it falls, what is the KE of the panther just before it hits the ground?

What was the velocity of the panther just before it hit the ground?

Answer 1

below

Step-by-step explanation:

PE = mgh = 62 * 9.81 * 1.3 = 791 J

now lose 200 J to air resistance = 591 J that is converted to kinetic energy

KE = 1/2 m v^2

591 = 1/2 (62)(v^2) shows v = 4.4 m/s