Question

I attached th eproblem.

Answer 1

`(7)/(b+4)`

Explanation:

`(7)/(b^2+5b+4)` ×
`(b^2+8b+7)/(b+7)` ← factor quadratics on numerator/ denominator

=
`(7)/((b+1)(b+4))` ×
`((b+1)(b+7))/(b+7)`

cancel factors (b+ 1) and (b + 7) on numerator/ denominator

=
`(7)/(b+4)` × 1

=
`(7)/(b+4)`