asked 64.8k views
4 votes
HOW Does 1/6, -3, square root 7, -6/5 or 45 come first when the numbers are listed from lest to greatest. explain PLEASE EXPLAIN ME!!!!!!!!!!!!!!!! :C(

asked
User Mnacos
by
8.6k points

2 Answers

4 votes

Answer:

-3 < -6/5 < 1/6 < √7 < 45

Explanation:

Now the values will be,

→ 1/6 = 0.17

→ -3 = -3

→ √7 = 2.65

→ -6/5 = -1.2

→ 45 = 45

Let's arrange in ascending order,

→ -3, -1.2, 0.17, 2.65, 45

→ -3, -6/5, 1/6, √7, 45

Hence, number -3 comes first.

answered
User Kaufman
by
7.6k points
7 votes

Answer:

  • - 3 comes first and the order is - 3, - 6/5, 1/6, √7, 45

==========================

Given numbers

  • 1/6, - 3, √7, - 6/5, 45.

Put these numbers in the ascending order

First, compare the negative numbers as they are smaller than positives since negatives are to the left from zero on the number line and positives are to the right.

  • - 3 vs - 6/5
  • - 3*5/ 5 vs - 6/5
  • - 15/5 vs - 6/5

Since - 15 is smaller than - 6, the least number is - 3:

  • - 15/5 < - 6/5 ⇒ - 3 < - 6/5

Now compare the positives.

  • 1/6 is smaller than 1 as it is a fraction.
  • √4 < √7 < √9 ⇒ 2 < √7 < 3, so √7 is between 2 and 3, hence greater than 1, therefore 1/6 < √7.
  • And the greatest number is 45 as it is greater than 3.

Therefore:

  • 1/6 < √7 < 45

The complete order is:

  • - 3, - 6/5, 1/6, √7, 45
answered
User Iefpw
by
8.4k points

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