Question

Hello If anyone is available.. I really need help on this. Question: 82 people were surveyed as to how many TVs they had in their homes.To one decimal place, what's the mean number of TVs owned by these households?

Answer 1

Using weighted mean, the mean is determined by

`\begin{gathered} \overline{x}=(\sum w_ix_i)/(w_i) \\ \text{where} \\ x_i\text{ are the data set} \\ w_i\text{ is the weight, or the frequency} \end{gathered}`
`\begin{gathered} \overline{x}=(\sum w_ix_i)/(w_i) \\ \overline{x}=(1\cdot0+1\cdot10+2\cdot24+3\cdot21+4\cdot16+5\cdot9+6\cdot1)/(1+10+24+21+16+9+1) \\ \overline{x}=(0+10+48+63+64+45+6)/(82) \\ \overline{x}=(236)/(82) \\ \overline{x}=2.87804878 \end{gathered}`

Rounding off to one decimal place, the mean number of TVs owned is 2.9.