Question

What force would be required to start pushing the 100 kg fridge if μs = 0.46?

Answer 1

Given data:

* The coefficient of static friction is,

`\mu_s=0.46`

* The mass of the fridge is m = 100 kg.

Solution:

The normal force acting on the fridge is,

`\begin{gathered} F_N=mg \\ F_N=100*9.8 \\ F_N=980\text{ N} \end{gathered}`

The frictional force acting on the fridge is,

`\begin{gathered} F_r=\mu_s* F_N \\ F_r=0.46*980 \\ F_r=450.8\text{ N} \end{gathered}`

The force required to start moving the fridge is equal to the frictional force.

Thus, the force required in the given case is 450.8 N.