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If there are 7 teams and every teams plays everyone once how many games total played

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This is a problem about combinations where the order doesn't matter. The solution is usually written as 7C2 (seven choose two) and has the value


(7!)/((7-2)!2!)=21

Comment: 7C2 is the answer to the question "How many pairs (in our case, these pairs are seen as games played) can we form from a group of 7 things?".

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