Question

Find the values of x and y in the equation below.a³b4a²b= a*b²X=

Answer 1

`((a^3b^4)/(a^2b))^6`

To divide, subtract exponents to same base variables.

`(ab^3)^6`

Multiply exponents of exponents

`a^6b^(18)`

x= 6

y= 18