Question

Solve x² + 6x + 7 = 0.x = -1 and x = -5 3+ √2-3+√2-3 ± √22

Answer 1

`x=-3\pm√(2)`

Step-by-step explanation

We want to solve for x in the equation:

`x^2+6x+7=0`

To do this, apply the quadratic formula:

`x=(-b\pm√(b^2-4ac))/(2a)`

where a = 1, b = 6, c = 7

Therefore, substituting the values of a, b, and c into the formula and solve:

`\begin{gathered} x=(-6\pm√(6^2-4(1)(7)))/(2(1))=(-6\pm√(36-28))/(2) \\ \\ x=(-6\pm√(8))/(2)=(-6\pm2√(2))/(2) \\ \\ x=-3\pm√(2) \end{gathered}`

That is the solution for x.