Question

An airplane is flying at an altitude of 6000 m over the ocean directly toward a coastline.At a certain time, the angle of depression to the coastline from the airplane is 14°. Howmuch farther (to the nearest meter) does the airplane have to fly before it is directlyabove the coastline?O 1496 mO 1451 mO 24065 mO 5822 m

Answer 1

In a diagram,

Solving for x (notice that we are dealing with a right triangle),

`\begin{gathered} tan(14\degree)=(6000)/(x) \\ \Rightarrow x=(6000)/(tan(14\degree))=1495.968...\approx1496 \end{gathered}`

Thus, the answer is 1496m, the first option.