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Consider the parent function P(x)=x2, a parabola that opens upward and passes through the points (−1,1), (0,0) and (1,1).Each of the following graphs shows P(x) as the preimage of the transformation and I(x) as the image of the transformation.Match each function rule of I(x) to its corresponding graph.

Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-1
Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-1
Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-2
Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-3
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User Igorzg
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9.0k points

1 Answer

6 votes

The parent function given is,


P(x)=x^2

Therefore,


I(x)=-4P(x)

The graph is shown below

Also,


I(x)=P(-4x)

The graph will be shown below

Next is,


I(x)=-(1)/(4)P(x)

The graph will be shown below

Lastly,


I(x)=P(-(1)/(4)x)

The graph will be shown below

Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-1
Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-2
Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-3
Consider the parent function P(x)=x2, a parabola that opens upward and passes through-example-4
answered
User Sergey Solod
by
8.2k points

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