Question

How many moles of Cr are there in a 92.3 g sample of chromium

Answer 1

To determine the number of moles, we look up in the periodic table the atomic weight of chromium, this is equal to 55.9961g/mol. And we apply the following relation:

`\begin{gathered} Mo_{}lC_{}r=\text{Given g of Cr}*\frac{1molCr}{\text{AtomicWeight, g Cr}} \\ Mo_{}lC_{}r=92.3\text{gCr}*(1molCr)/(55.9961gCr)=1.6\text{mol Cr} \end{gathered}`

There are 1.6 moles of Cr in 92.3g sample