Question

A number one fourth of that number, and one third of that number are added. The result is 38. What is the original number? Check your solution.

Answer 1

Let the number be x, we have

`\begin{gathered} x+(x)/(4)+(x)/(3)\text{ =38} \\ (12x+3x+4x)/(12)=38 \\ (19x)/(12)=38 \end{gathered}`

cross multiply

`\begin{gathered} 19x\text{ = 456} \\ x\text{ = }(456)/(19) \\ x=24 \end{gathered}`

The original number is 24