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Solve for x 7x^2+49=0

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Answer:


7 {x}^(2) + 49 = 0 \\ 7( {x}^(2) + 7) = 0 \\ \frac{7( ({x}^(2) + 7) }{7} = (0)/(7) \\ {x}^(2) + 7 = 0 \\ {x}^(2) = - 7

NOTE THERE IS NO SOLUTION FOR THE GIVEN EQUATION SINCE THE SQUARE OF ANY NUMBER CANNOT GIVE A NEGATIVE NUMBER.

THE SQUARE OF ANY NUMBER WHETHER IT'S POSITIVE OR NEGATIVE ALWAYS GIVES A POSITIVE NUMBER.

GOODLUCK!!

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User Jonathan Oliver
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