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3 votes
What is the vertex of Y=x^2+4x+9

asked
User VPfB
by
8.3k points

1 Answer

6 votes

Answer:

The vertex is at the point;


(-2,5)

Step-by-step explanation:

Given the function;


y=x^2+4x+9

Comparing to the quadratic equation;


y=ax^2+bx+c

The vertex is at;


x=(-b)/(2a)

For the given equation;


\begin{gathered} a=1 \\ b=4 \end{gathered}

substituting;


\begin{gathered} x=-(b)/(2a)=-(4)/(2(1)) \\ x=-2 \end{gathered}

The value of y at x=-2 is;


\begin{gathered} y=x^2+4x+9 \\ y=(-2)^2+4(-2)+9 \\ y=4-8+9 \\ y=5 \end{gathered}

Therefore, the vertex is at the point;


(-2,5)

answered
User Martin Meixger
by
8.5k points

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