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A bag contains 16 marbles 6 are pink, 3 are blue, 4 are green, and the rest are purple. Miamar randomly selects two marbles vithout replacing them. Whatis the probability that the marble she will selects first is green and the second one is blus?

A bag contains 16 marbles 6 are pink, 3 are blue, 4 are green, and the rest are purple-example-1

1 Answer

4 votes

The Solution.

We shall tabulate the given information as below:


\begin{gathered} \text{Probability of selecting }a\text{ pink marble is given as below:} \\ \text{Prob(P) =}(6)/(16) \end{gathered}

The probability of selecting a blue marble is given as below:


\text{Prob(B)}=(3)/(16)

The probability of selecting a green marble is obtained as below:


\text{Prob(G) =}(4)/(16)

The probability of selecting a purple marble is obtained as below:


\text{Prob(Purple) =}(3)/(16)

The probability of randomly selecting 2 marbles, of which the first is green and the second is blue, is obtained as below


\begin{gathered} \text{Prob(G}_1B_2)=prob(G_1)* prob(B_2) \\ \text{ =}(4)/(16)*(3)/(15)=(1)/(4)*(1)/(5)=(1)/(20) \end{gathered}

Note: T

A bag contains 16 marbles 6 are pink, 3 are blue, 4 are green, and the rest are purple-example-1
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User Eder
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