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4 votes
Find the derivative of
h(x) = {4}^{ (x)/(2) } \sin(2x)

asked
User Jammi
by
8.1k points

1 Answer

3 votes

The given expression is:


\begin{gathered} \\ h(x)={4}^{(x)/(2)}\sin (2x) \end{gathered}

To find the derivative, use the product rule:


\begin{gathered} (dh)/(dx)=\text{ U}(dV)/(dx)+V(dU)/(dx) \\ U=4^{(x)/(2)} \\ (dU)/(dx)=\text{ }\frac{4^{(x)/(2)}\ln 4}{2} \\ V\text{ = sin(2x)} \\ (dV)/(dx)=\text{ 2}\cos (2x) \end{gathered}

Substitute, U, V, dU/dx, and dV/dx into the product rule given above:


undefined

answered
User Oliver Nybroe
by
8.3k points

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