Question

Rewrite the following in logarithmic form:a) 6 to 3rd power (sorry my superscript short cut isn't working) = 216b) 10 to the 0 power =xc) e to the x power =28

Answer 1

Part a

we have

`6^3=216`

so

in logarithmic form

`\log _6216=3`

Part b

`10^0=x`

in logarithmic form

`\begin{gathered} \log _(10)x=0 \\ \log x=0 \end{gathered}`

Part c

we have

`e^x=28`

in logarithmic form

`\ln 28=x`