Question

(0,2) and(8,0) Write an equation in standard form of the line that passes through the given points

Answer 1

To find the equation of a line that pasess through two ponit, we'll first have to calculate the slope, using the formula:

`m=\frac{y_2-y^{}_1}{x_2-x_1}`

Therefore,

`m=(0-2)/(8-0)\rightarrow m=(-2)/(8)\rightarrow m=-(1)/(4)`

Then, we use the point-slope form equa with the slope we just found and the point (8,0)

`\begin{gathered} y-0=-(1)/(4)(x-8)\rightarrow y=-(1)/(4)x+2\rightarrow y-2=-(1)/(4)x \\ \rightarrow-4y+8=x\rightarrow8=x+4y \\ \text{Therefore, the equation of the line is:} \\ x+4y=8 \end{gathered}`