For this question, we need to us the equatio ratio between H2O and HNO3 to find out how many grams of water can be made when 8.8 moles of HNO3 are consumed.
Let's rewrite the equation here:
3 Cu + 8 HNO3 ---> 3 Cu(NO3)2 + 2 NO + 4 H2O
- In this equation, when 8 moles of HNO3 are consumed, 4 moles of H2O are formed.
So:
8 moles of HNO3 ---- 4 moles of H2O
8.8 moles of HNO3 ---- x moles of H2O
8x = 8.8 x 4
x = 35.2/8
x = 4.4 moles of H2O
- Now we need to transform moles of H2O into grams of H2O. For this, we use the following equation: mass = mole x molar mass
molar mass of H2O: (2x1) + (1x16) = 18 g/mol
mass = 4.4 x 18
mass = 79.2 g
Answer: 79 g of water